温州自助建站公司,什么是网站的备案号,龙岗商城网站建设教程,样式模板网站求二元函数z0.2323*x^2-0.2866^22*(-0.5406)*a0^21.0203*a0^2*x^2/((x^2y^2)^0.5*tanh(2*(x^2y^2)^0.5)-x^2*(0.5733-u0)^2)的最大值#xff0c;变量x和y都是在0.2附近。求z的最大值#xff0c;以及x,y的取值。先用diff命令求z关于x,y的偏导数得到q(1)和q(2)两个方程#xf…求二元函数z0.2323*x^2-0.2866^22*(-0.5406)*a0^21.0203*a0^2*x^2/((x^2y^2)^0.5*tanh(2*(x^2y^2)^0.5)-x^2*(0.5733-u0)^2)的最大值变量x和y都是在0.2附近。求z的最大值以及x,y的取值。先用diff命令求z关于x,y的偏导数得到q(1)和q(2)两个方程再用fsolve求解方程组想得到各驻点的坐标但一直不成功只得到x0,y0;程序如下function qmyfun(p)xp(1);yp(2);q(1)(1046382468744793*x)/2251799813685248 (2940675037869895*x)/(144115188075855872*(tanh(2*(x^2 y^2)^(1/2))*(x^2 y^2)^(1/2) - (2960289404442881*x^2)/9007199254740992)) (2940675037869895*x^2*((2960289404442881*x)/4503599627370496 2*x*(tanh(2*(x^2 y^2)^(1/2))^2 - 1) - (x*tanh(2*(x^2 y^2)^(1/2)))/(x^2 y^2)^(1/2)))/(288230376151711744*(tanh(2*(x^2 y^2)^(1/2))*(x^2 y^2)^(1/2) - (2960289404442881*x^2)/9007199254740992)^2);q(2)(2940675037869895*x^2*(2*y*(tanh(2*(x^2 y^2)^(1/2))^2 - 1) - (y*tanh(2*(x^2 y^2)^(1/2)))/(x^2 y^2)^(1/2)))/(288230376151711744*(tanh(2*(x^2 y^2)^(1/2))*(x^2 y^2)^(1/2) - (2960289404442881*x^2)/9007199254740992)^2) - (1290927876507717*y)/2251799813685248main % 主程序x0 [0.2;0.2]; % 初值options optimoptions(fsolve,Display,iter);[x,fval] fsolve(myfun,x0,options),谢谢。
