荥阳网站建设,怎么做网上直营店网站,重庆建网站价格,中国电子商务平台本题新学知识点#xff1a; itoa函数 char *itoa( int value, char *string,int radix);[1]原型说明#xff1a;value#xff1a;欲转换的数据。string#xff1a;目标字符串的地址。radix#xff1a;转换后的进制数#xff0c;可以是10进制、16进制等。程序实例:#includ… 本题新学知识点 itoa函数 char *itoa( int value, char *string,int radix);[1] 原型说明 value欲转换的数据。 string目标字符串的地址。 radix转换后的进制数可以是10进制、16进制等。 程序实例: #include stdlib.h #include stdio.h int main(void) { int number 12345; char string[32]; itoa(number, string, 10); printf(integer %d string %s\n, number, string); return 0; } 1 /*2 设计思路3 1.判断是否有乘除法4 2.规定数值范围通过random乘数值5 3.加减有无负数两个数值随机产生符号6 4.除法有无余数7 */8 9 #includeiostream10 #includetime.h11 #includestring12 # include stdio.h13 #includestdlib.h14 #includeiomanip15 #includecmath 16 using namespace std;17 18 //1.乘除法19 int chengchu()20 {21 char X;22 cout 请选择要产生几以内的四则运算10 or 100;23 int range;24 cin range;25 26 cout 1.是否需要乘除法运算Y or N\n;27 cin X;28 29 if (X Y)30 {31 32 for (int count 0; count 5; count)33 {34 int a 0, b 0;35 36 a rand() % range;37 b rand() % range ;38 39 //随机产生四则运算符40 int sign 0;41 sign (rand() % 100) % 2;42 string opera_sign[2] { *, / };43 44 //当b0且运算为除法时重新生成45 while ((b 0) (sign 1))46 {47 b rand() % range;48 }49 50 switch (sign)51 {52 case 0:cout a opera_sign[sign] b endl; break;53 case 1:cout a opera_sign[sign] b endl; break;54 }55 }56 }57 if (X N)58 {59 60 for (int count 0; count 5; count)61 {62 int a 0, b 0;63 64 a rand() % range;65 b rand() % range;66 67 //随机产生四则运算符68 int sign 0;69 sign (rand() % 100) % 2;70 string opera_sign[2] { , - };71 72 switch (sign)73 {74 case 0:cout a opera_sign[sign] b endl; break;75 case 1:cout a opera_sign[sign] b endl; break;76 }77 }78 }79 return 0;80 }81 82 //2.包含真分数83 int fenshu()84 {85 char Z;86 cout 2.是否包含真分数Y or N\n;87 cin Z;88 if (Z Y)89 {90 for (int count 0; count 5; count)91 {92 int a1 0, b1 0, a2 0, b2 0;93 94 a1 rand() % 100;95 b1 rand() % 100;96 a2 rand() % 100;97 b2 rand() % 100;98 99 //判断是否为真分数
100 while (a1b1 || b1 0)
101 {
102 a1 rand() % 100;
103 b1 rand() % 100;
104 }
105
106 while (a2 b2 || b2 0)
107 {
108 a2 rand() % 100;
109 b2 rand() % 100;
110 }
111
112 //随机产生四则运算符
113 int sign 0;
114 sign (rand() % 100) % 4;
115 string opera_sign[4] { , -, *, / };
116
117 switch (sign)
118 {
119 case 0:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
120 case 1:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
121 case 2:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
122 case 3:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
123 }
124 }
125 }
126 if (Z N)
127 {
128 for (int count 0; count 5; count)
129 {
130 int a1 0, b1 0, a2 0, b2 0;
131
132 a1 rand() % 100;
133 b1 rand() % 100;
134 a2 rand() % 100;
135 b2 rand() % 100;
136
137 //分母不可为0
138 while (b1 0)
139 {
140 b1 rand() % 100;
141 }
142 while (b2 0)
143 {
144 b2 rand() % 100;
145 }
146
147 //随机产生四则运算符
148 int sign 0;
149 sign (rand() % 100) % 4;
150 string opera_sign[4] { , -, *, / };
151
152 switch (sign)
153 {
154 case 0:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
155 case 1:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
156 case 2:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
157 case 3:cout ( a1 / b1 ) opera_sign[sign] ( a2 / b2 ) endl; break;
158 }
159 }
160 }
161 return 0;
162 }
163
164 //把数字转换成字符串型
165 string int_string(int number)
166 {
167 char str1[200];
168 itoa(number, str1, 10);
169 string str_ str1;
170 return str_;
171 }
172
173 int kuohao()
174 {
175 char K;
176 cout 3.是否包含括号Y or N\n;
177 cin K;
178 if (K Y)
179 {
180 string stri[4];
181 for (int i 0; i 4; i)
182 {
183 int a 0, b 0;
184 a rand() % 100;
185 b rand() % 100;
186
187 int sign 0;
188 sign (rand() % 100) % 4;
189 string opera_sign[4] { , -, *, / };
190
191 //当b0且运算为除法时重新生成
192 while ((b 0) (sign 3))
193 {
194 b rand() % 100;
195 }
196 string str,ch1, ch2;
197
198 ch1 int_string(a);
199 ch2 int_string(b);
200 //string stri[4];
201
202 switch (sign)
203 {
204 case 0:
205 {
206 str ( ch1 opera_sign[sign] ch2 );
207 } break;
208
209 case 1:
210 {
211 str ( ch1 opera_sign[sign] ch2 );
212 }break;
213
214 case 2:
215 {
216 str ( ch1 opera_sign[sign] ch2 );
217 } break;
218
219 case 3:
220 {
221 str ( ch1 opera_sign[sign] ch2 );
222 }break;
223 }
224 stri[i] str;
225 }
226
227 string str5;
228 // str5 (( stri[0] stri[1] ) stri[2] ) stri[3];
229 cout (( stri[0] stri[1] )*stri[2] ) / stri[3];
230 }
231
232 else
233 {
234 cout endl;
235 }
236
237
238 }
239 //主函数
240 int main()
241 {
242 //以现在的系统时间作为随机数的种子来产生随机数
243 srand(time(NULL));
244 cout 请您选择四则运算题的条件\n;
245 int result1 chengchu();
246 int result2 fenshu();
247 int result3 kuohao();
248 return 0;
249 } 转载于:https://www.cnblogs.com/X-knight/p/5269542.html
