艺术学院网站建设,网站案例介绍,做一个网站大概多少钱,网站建设语基本矩阵运算的Java实现 分类#xff1a; 图像处理2012-09-18 10:36 2537人阅读 评论(3) 收藏 举报javamatrixparametersstringclassnull一#xff1a; 矩阵的加法与减法 规则#xff1a;矩阵的加法与减法要求两个矩阵的行列完全相等#xff0c;方可以完成两个矩阵的之间的… 基本矩阵运算的Java实现 分类 图像处理2012-09-18 10:36 2537人阅读 评论(3) 收藏 举报 javamatrixparametersstringclassnull 一 矩阵的加法与减法 规则矩阵的加法与减法要求两个矩阵的行列完全相等方可以完成两个矩阵的之间的运算。 举例说明如下 二矩阵的乘法 规则矩阵的乘法要求两个矩阵符合A(mx k), B( k x n)即矩阵A的列数与矩阵B的行数相等否 则无法完成矩阵运算。举例说明如下 Java代码如下 [java] view plaincopy package pet.shop; public class BasicMatrixMath { public final static int OPERATION_ADD 1; public final static int OPERATION_SUB 2; public final static int OPERATION_MUL 4; /** * To be able to add two matrices, they must be of the same size * param matrixa * param matrixb */ public int[][] add(int[][] matrixa, int[][] matrixb) { if(legalOperation(matrixa, matrixb, OPERATION_ADD)) { for(int i0; imatrixa.length; i) { for(int j0; jmatrixa[0].length; j) { matrixa[i][j] matrixa[i][j] matrixb[i][j]; } } } return matrixa; } /** * To be able to substract two matrices, they must be of the same size * * param matrixa * param matrixb */ public int[][] substract(int[][] matrixa, int[][] matrixb) { if(legalOperation(matrixa, matrixb, OPERATION_SUB)) { for(int i0; imatrixa.length; i) { for(int j0; jmatrixa[0].length; j) { matrixa[i][j] matrixa[i][j] - matrixb[i][j]; } } } return matrixa; } /** * * param matrixa * param matrixb */ public int[][] multiplication(int[][] matrixa, int[][] matrixb) { if(legalOperation(matrixa, matrixb, OPERATION_SUB)) { int[][] result new int[matrixa.length][matrixb[0].length]; for(int i0; imatrixa.length; i) { for(int j0; jmatrixb[0].length; j) { // i will complete this tomorrow 2012/09/17 result[i][j] calculateSingleResult(matrixa, matrixb, i, j); } } return result; } else { return null; } } private int calculateSingleResult(int[][] matrixa, int[][] matrixb, int row, int col) { int result 0; for(int k0; kmatrixa[0].length; k) { result matrixa[row][k] * matrixb[k][col]; } return result; } /** * * param matrixa * param b */ public int[][] multiplication(int[][] matrixa, int b) { for(int i0; imatrixa.length; i) { for(int j0; jmatrixa[0].length; j) { matrixa[i][j] matrixa[i][j] * b; } } return matrixa; } /** * validate whether the parameters is valid parameters. * * param a * param b * param type * return */ private boolean legalOperation(int[][] a, int[][] b, int type) { boolean legal true; if(type OPERATION_ADD || type OPERATION_SUB) { if(a.length ! b.length || a[0].length ! b[0].length) { legal false; } } else if(type OPERATION_MUL) { if(a[0].length ! b.length) { legal false; } } return legal; } /** * test code here !!!! * param args */ public static void main(String[] args) { int[][] a new int[][]{{1,2},{3,4}}; int[][] b new int[][]{{7, 8}, {6, 5}}; BasicMatrixMath bmm new BasicMatrixMath(); System.out.println(addition two matrix); int[][] result bmm.add(a, b); for(int i0; iresult.length; i) { for(int j0; jresult[0].length; j) { System.out.print(\t result[i][j]); } System.out.println(); } System.out.println(substract two matrix); result bmm.substract(a, b); for(int i0; iresult.length; i) { for(int j0; jresult[0].length; j) { System.out.print(\t result[i][j]); } System.out.println(); } System.out.println(multiplex one matrix); result bmm.multiplication(a, 3); for(int i0; iresult.length; i) { for(int j0; jresult[0].length; j) { System.out.print(\t result[i][j]); } System.out.println(); } System.out.println(multiplex two matrix); result bmm.multiplication(a, b); for(int i0; iresult.length; i) { for(int j0; jresult[0].length; j) { System.out.print(\t result[i][j]); } System.out.println(); } } } 转载于:https://www.cnblogs.com/jamesf/p/4751601.html
